Chemistry of Life
Unit 1 of AP Biology, worth 8–11% of the exam. 13 questions below, each with the working. Every answer was checked by a second pass before it was published.
Water and its properties, biological macromolecules (carbohydrates, lipids, proteins, nucleic acids), monomers and polymers, and how structure determines function.
How this unit is tested
What you have to know
13 practice questions
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Which property of water is most directly responsible for its ability to moderate temperature changes in aquatic environments?
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Answer. High specific heat, caused by the many hydrogen bonds that must absorb or release energy before water's temperature changes
Hydrogen bonds absorb heat energy when they break and release it when they form, so a large amount of energy is needed to change water's temperature, buffering aquatic habitats against rapid swings. -
Explain at the molecular level why ice floats on liquid water.
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Answer. Hydrogen bonds in ice lock water molecules into a fixed, spread-out crystalline lattice, making ice less dense than the more randomly packed molecules in liquid water.
In liquid water, hydrogen bonds constantly break and reform, allowing molecules to pack closely. In ice, each molecule forms four stable hydrogen bonds in a rigid hexagonal lattice that takes up more space, lowering density. -
A biologist observes water molecules clinging to the walls of a plant's xylem vessel as water is pulled upward. This clinging behavior is best explained by which property?
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Answer. Adhesion
Adhesion is the attraction of water molecules to a different polar substance (here, the polar cellulose walls of the xylem), which along with cohesion drives capillary action. -
Describe the reaction that links two monosaccharides into a disaccharide, and name the reverse reaction.
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Answer. Dehydration synthesis forms a glycosidic bond between the two monosaccharides and releases a water molecule; the reverse reaction, hydrolysis, adds a water molecule to break the bond back into two monosaccharides.
This monomer-to-polymer/polymer-to-monomer relationship applies across all four macromolecule classes, not just carbohydrates. -
Which polysaccharide provides structural support in fungal cell walls and the exoskeletons of arthropods?
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Answer. Chitin
Chitin is a structural polysaccharide made of modified glucose monomers containing nitrogen groups, giving it rigidity used in fungal cell walls and insect exoskeletons, distinct from energy-storage polysaccharides like starch and glycogen. -
Explain why cellulose is not digestible by most animals even though it is made of the same glucose monomers as starch.
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Answer. Cellulose's glucose units are joined by beta-1,4 glycosidic bonds, producing straight chains that hydrogen-bond into rigid fibers; most animals lack enzymes that can break beta linkages, unlike the alpha-1,4 bonds in starch that form a helical, easily hydrolyzed structure.
This is a classic structure-function comparison: identical monomers, different bond geometry, different digestibility and function (structural vs. energy storage). -
Which macromolecule has an amphipathic structure, with a polar phosphate-containing head and nonpolar fatty acid tails, that allows it to spontaneously form a bilayer in water?
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Answer. Phospholipid
The polar head interacts favorably with water while the nonpolar tails avoid it, driving phospholipids to self-assemble into a bilayer with tails facing inward, forming the basis of cell membranes. -
A point mutation causes glutamic acid to be replaced by valine at one position in the hemoglobin beta chain (as in sickle cell disease). Explain how this affects protein structure and function.
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Answer. The substitution changes the primary structure; because valine is nonpolar and hydrophobic while glutamic acid is polar and charged, the altered R-group changes folding and surface interactions, disrupting tertiary/quaternary structure and causing hemoglobin molecules to aggregate into rigid fibers under low oxygen, which distorts red blood cell shape and impairs oxygen transport.
This illustrates the theme that a single change in primary structure can cascade into altered higher-order structure and a measurable loss of function. -
Denaturation caused by heat or extreme pH disrupts which levels of protein structure, while typically leaving which level intact?
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Answer. It disrupts secondary, tertiary, and quaternary structure while leaving primary structure (the peptide bond sequence) intact.
Denaturing conditions break the weaker hydrogen bonds, ionic interactions, and disulfide bridges that maintain folding, but the strong covalent peptide bonds of the primary sequence are not broken. -
List the three components of a nucleotide, and state one sugar difference and one base difference between DNA and RNA.
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Answer. A nucleotide consists of a phosphate group, a five-carbon sugar, and a nitrogenous base. DNA's sugar is deoxyribose while RNA's is ribose; DNA uses thymine as a base while RNA uses uracil in its place.
These structural differences underlie DNA's stability for long-term information storage versus RNA's more transient, versatile roles. -
Using the concept of induced fit, explain why an enzyme's active site is specific to a particular substrate.
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Answer. The active site's amino acid R-groups create a three-dimensional shape and chemical environment (charge, polarity, hydrophobicity) complementary to a specific substrate; binding causes a slight conformational change that improves the fit, so only molecules matching that shape and chemistry bind efficiently and react.
This directly ties protein tertiary structure to biological function: change the active site's shape (e.g., via mutation or denaturation) and the enzyme loses specificity or activity. -
A solution has a pH of 3, and another has a pH of 6. How many times greater is the hydrogen ion concentration in the pH 3 solution?
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Answer. 1000 times greater
pH is a negative log scale, so each one-unit drop in pH means a tenfold increase in [H⁺]. A difference of 3 pH units corresponds to $10^3$, or 1000 times more H⁺. -
Explain the role of the bicarbonate buffer system in maintaining blood pH homeostasis.
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Answer. Bicarbonate (HCO₃⁻) can accept excess H⁺ ions to form carbonic acid, and carbonic acid can release H⁺ when pH rises, allowing the system to resist large shifts in pH by reversibly absorbing or releasing hydrogen ions as conditions change.
Buffers like bicarbonate keep blood pH within a narrow physiological range despite metabolic production of acids such as CO₂-derived carbonic acid.
What people get wrong
- Reversing dehydration synthesis and hydrolysis: students say water is released during digestion. Fix: hydrolysis (breaking polymers, e.g., digestion) adds water; dehydration synthesis (building polymers) removes water.
- Treating cellulose and starch as chemically identical because both are glucose polymers. Fix: identify the glycosidic bond type — alpha-1,4 (starch, digestible, helical) versus beta-1,4 (cellulose, indigestible by most animals, rigid fibers).
- Assuming every protein has quaternary structure. Fix: quaternary structure only exists if the functional protein is made of more than one polypeptide chain (e.g., hemoglobin); a single-chain protein like myoglobin stops at tertiary structure.
- Attributing a bulk property of water (like high specific heat) to one single hydrogen bond. Fix: explain these properties as emerging from the collective, constantly reforming network of many hydrogen bonds, not one bond's strength.
- Confusing saturated and unsaturated fats by their names alone. Fix: saturated means saturated with hydrogen (no C=C double bonds, straight chains, pack tightly, solid at room temp); unsaturated has one or more double bonds causing kinks that prevent tight packing.
Drill this unit until it sticks
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