AP Physics 1
College Board · 8 units · exam-weighted · high school
AP Physics 1: every unit with its share of the exam, as College Board publishes it, with practice questions per unit and a countdown to the exam.
Set up AP Physics 1 → One set per unit, 8 of them pre-written and answer-checked. Free, no account needed.
Units and exam weighting
Unit 1: Kinematics 10–15% of the exam
Scalars and vectors, displacement, velocity and acceleration, representations of motion, reference frames, motion in two dimensions.
3 of 13 questions in this unit, with the worked answer
A runner completes one full lap around a 400 m circular track, returning exactly to the starting point. What are the runner's total distance traveled and total displacement?
Answer. Distance = 400 m; displacement = 0 m.
An object's position is x(t) = 3t^2 − 2t (in meters, t in seconds). Find its instantaneous velocity at t = 2 s.
Answer. 10 m/s
A velocity-time graph shows an object's velocity increasing linearly from 0 to 8 m/s over 4 seconds, then remaining constant at 8 m/s for the next 2 seconds. What is the total displacement over the 6 seconds?
Answer. 32 m
What people get wrong
- Treating speed and velocity as interchangeable. Speed is the magnitude of velocity and is always positive; velocity carries direction and can be negative. Always ask whether the question wants magnitude only or a signed/directional answer.
- Applying the four kinematic equations when acceleration is not constant (e.g., during a curved velocity-time graph). Instead, use the definitions of average velocity/acceleration or read slopes and areas directly off the graph.
- Assuming horizontal velocity changes during projectile motion. In the absence of air resistance, a_x = 0, so horizontal velocity is constant throughout the flight — only vertical velocity changes.
- Forgetting to decompose the initial velocity into components when a projectile is launched at an angle, and mistakenly plugging the full speed into the vertical equations. Always split into v0x and v0y first.
Unit 2: Force and Translational Dynamics 18–23% of the exam
Systems and centre of mass, forces and free-body diagrams, Newton's three laws, gravitational force, friction, springs, circular motion.
3 of 14 questions in this unit, with the worked answer
A net force of 12 N acts on a 3 kg object initially at rest. What is its speed after 4 seconds?
Answer. 16 m/s
A 2 kg block and a 3 kg block are in contact on a frictionless surface. A 10 N horizontal force pushes on the 2 kg block, which pushes into the 3 kg block. What is the contact force between the blocks?
Answer. 6 N
A book rests on a table. Which of the following is the Newton's third law pair to the gravitational force of Earth on the book?
Answer. The gravitational force of the book on Earth
What people get wrong
- Using $mg$ as the normal force on an incline instead of $mg\cos\theta$. Always find the normal force by balancing forces perpendicular to the incline's surface, not the horizontal.
- Applying $f_k = \mu_kN$ to an object that is not actually sliding. Check whether the applied force exceeds $\mu_sN$ first; if it doesn't, the object stays at rest and friction equals the applied force, not $\mu_kN$.
- Pairing the normal force and weight as a Newton's third law pair because they're equal and opposite. They act on the same object and are different types of force, so they cannot be a third-law pair; true pairs act on different objects.
- Treating 'centripetal force' as an extra force to add to the free-body diagram. It is not a new force — it's the label for the net force (or the net radial component of existing forces) that must point toward the center.
Unit 3: Work, Energy, and Power 18–23% of the exam
Translational kinetic energy, work, potential energy, conservation of energy, power.
3 of 14 questions in this unit, with the worked answer
A 0.50 kg ball moves at 12 m/s. What is its translational kinetic energy?
Answer. 36 J
An object moves in a horizontal circle at constant speed, held by a string that provides the centripetal force. Which force does zero work on the object?
Answer. The tension providing centripetal force
A net force does 150 J of work on a 3.0 kg object that starts at rest. Find its final speed.
Answer. 10 m/s
What people get wrong
- Forgetting the $\cos\theta$ factor when a force isn't parallel to displacement, treating $W=Fd$ even when the force is applied at an angle. Always identify the angle between the force vector and the displacement vector first.
- Assuming forces like the normal force or the tension in circular motion do work simply because they are large. If a force is perpendicular to the object's displacement at every instant, it does exactly zero work.
- Using the length traveled along an incline instead of the vertical height change when computing gravitational potential energy. Only $\Delta h$ (vertical) matters for $\Delta PE_{grav}$, not the path length.
- Applying $KE_i+PE_i=KE_f+PE_f$ when friction or another non-conservative force is present. Check the force list first; if friction acts, add a $W_{nc}$ term or the answer will overestimate final speed or height.
Unit 4: Linear Momentum 10–15% of the exam
Momentum, impulse, change in momentum, conservation of momentum, elastic and inelastic collisions.
3 of 14 questions in this unit, with the worked answer
A 3 kg object moves at 4 m/s. What is its momentum?
Answer. 12 kg·m/s in the direction of motion
A net force of 15 N acts on a 5 kg object at rest for 2 seconds. What is the object's final speed?
Answer. 6 m/s
Which quantity is conserved in an isolated system for both elastic and inelastic collisions?
Answer. Total momentum
What people get wrong
- Treating momentum as a scalar and dropping signs. Fix: pick one positive direction before writing any equation, and give every velocity (including 'at rest' as zero) a signed value consistent with that choice.
- Assuming kinetic energy is conserved in every collision. Fix: only assume KE conservation if the problem explicitly states 'elastic' or you have verified it by calculation; otherwise treat KE as unknown and solve using momentum alone.
- Applying conservation of momentum to a system that isn't isolated, such as ignoring friction, an incline, or an external push during the interaction. Fix: check that the net external force is zero (or that the interaction time is short enough that external impulses are negligible) before conserving momentum.
- Confusing impulse with force. Fix: remember impulse is $F\Delta t$, a quantity that depends on both the force and how long it acts; a small force over a long time can deliver the same impulse as a large force over a short time.
Unit 5: Torque and Rotational Dynamics 10–15% of the exam
Rotational kinematics, torque, rotational inertia, rotational equilibrium and Newton's first law in rotational form, Newton's second law for rotation.
3 of 14 questions in this unit, with the worked answer
Which quantity describes an object's resistance to changes in its angular velocity, depending on both mass and how it is distributed relative to the axis?
Answer. Rotational inertia (moment of inertia)
A wheel starts from rest and undergoes a constant angular acceleration of 2.0 rad/s². What is its angular velocity after 5.0 s?
Answer. 10 rad/s
The wheel from the previous problem has radius 0.30 m. What is the tangential (linear) speed of a point on its rim at t = 5.0 s?
Answer. 3.0 m/s
What people get wrong
- Using the full distance r in torque instead of the lever arm — a force applied at an angle to the object contributes only its perpendicular component. Always multiply by $\sin\theta$, or find the true perpendicular distance from the axis to the force's line of action.
- Assuming equilibrium is satisfied once $\sum F=0$ is checked. Rotational equilibrium requires $\sum \tau=0$ as a separate, independent condition — a pair of equal and opposite forces on opposite ends of an object can satisfy $\sum F=0$ while still spinning the object up.
- Treating rotational inertia as if it only depended on total mass. Two objects with identical mass and radius (a disk and a hoop) have very different I because the hoop's mass sits farther from the axis on average — always check how mass is distributed, not just how much there is.
- Losing track of sign convention when several torques act. Pick counterclockwise (or clockwise) as positive once, and apply it consistently to every torque in the equation, including ones that seem 'obviously' negative.
Unit 6: Energy and Momentum of Rotating Systems 5–8% of the exam
Rotational kinetic energy, torque and work, angular momentum and impulse, conservation of angular momentum, rolling, orbits and satellites.
3 of 14 questions in this unit, with the worked answer
A rotating wheel has moment of inertia $I=4\,kg\cdot m^2$ and angular speed $\omega=3\,rad/s$. What is its rotational kinetic energy?
Answer. 18 J
A constant torque of 5 N·m rotates a wheel through one full revolution (2π rad) starting from rest. How much work is done on the wheel by this torque?
Answer. About 31.4 J
A 2 kg particle moves in a circle of radius 0.5 m at a constant speed of 3 m/s. What is the magnitude of its angular momentum about the center of the circle?
Answer. 3 kg·m²/s
What people get wrong
- Computing only $\frac12mv^2$ for a rolling object's kinetic energy. Instead, always add the rotational term $\frac12I\omega^2$ using the rolling constraint $\omega=v/r$.
- Assuming angular speed stays constant when moment of inertia changes (e.g., a skater pulling in arms). Instead, recognize that angular momentum $L=I\omega$ is what's conserved, so $\omega$ must increase as $I$ decreases.
- Using $L=mvr$ even when the velocity isn't perpendicular to the position vector. Instead, use $L=mvr\sin\theta$, or identify the perpendicular distance (lever arm) directly.
- Treating the static friction force in rolling-without-slipping problems as if it dissipates energy. Instead, remember static friction does zero work (the contact point has zero velocity), so mechanical energy is still conserved.
Unit 7: Oscillations 5–8% of the exam
Simple harmonic motion, frequency and period, representing and analysing SHM, energy in simple harmonic oscillators.
3 of 14 questions in this unit, with the worked answer
Which condition must be satisfied for a system's motion to be classified as simple harmonic motion?
Answer. The net force must be proportional to the displacement from equilibrium and directed toward it.
A block of mass 0.50 kg is attached to a spring with spring constant 200 N/m. Find the period of oscillation.
Answer. T ≈ 0.31 s
An oscillator completes one full cycle every 0.25 s. What is its frequency?
Answer. 4 Hz
What people get wrong
- Assuming a larger amplitude makes the period longer or shorter. For ideal SHM (spring or small-angle pendulum), period depends only on m,k or L,g — never on amplitude. Check the formula, not intuition, before answering period questions.
- Thinking speed is maximum at the turning points (x = ±A). Speed is actually zero there and maximum at equilibrium (x = 0); acceleration is the one that's maximum at the extremes. Sketch the motion before assigning max/min values.
- Mixing up which variables affect which period. Mass matters for a spring's period but not for a pendulum's; length matters for a pendulum but has no meaning for a spring. Always match the formula to the physical system.
- Applying the small-angle pendulum formula T = 2π√(L/g) to large swing angles. The formula breaks down above roughly 15°, and the real period becomes amplitude-dependent — don't assume the simple formula always holds.
Unit 8: Fluids 10–15% of the exam
Internal structure and density, pressure, fluids and Newton's laws, buoyancy, conservation of mass flow rate, conservation of energy in fluid flow (Bernoulli).
3 of 14 questions in this unit, with the worked answer
A metal cube has edge length 2.0 cm and mass 21.6 g. Calculate its density in kg/m³ and state whether it is more likely aluminum (2700 kg/m³) or gold (19,300 kg/m³).
Answer. About 2700 kg/m³, so aluminum.
A 60 kg person stands with both feet on the floor, and each foot contacts an area of 150 cm². What pressure does the person exert on the floor? (g = 9.8 m/s²)
Answer. About 2.0×10⁴ Pa (19,600 Pa).
Three containers with different shapes (narrow, wide, and irregular) are each filled with water to the same height. How do the pressures at the bottom of the three containers compare?
Answer. All three pressures are equal.
What people get wrong
- Forgetting the atmospheric pressure term when a problem asks for absolute pressure at a depth. Instead, always check whether the question wants gauge pressure (just $\rho g h$) or absolute pressure (must add $P_0$).
- Using mass instead of weight in buoyancy problems, e.g. computing $F_b=\rho V$ and forgetting the factor of $g$. Instead, always write $F_b=\rho_{fluid}V_{displaced}g$ and check units come out in newtons.
- Assuming buoyant force depends on the object's own density or weight. Instead, remember buoyant force depends only on the fluid's density and the volume displaced — the object's density only determines whether it floats or sinks.
- Mixing up which area is A1 and which is v1 in the continuity equation, leading to an inverted answer (getting a slower speed in the narrower section). Instead, remember flow speeds up where the pipe narrows: smaller area always pairs with larger speed.
How it works
Choosing this curriculum creates a course in Chalkset with one study set per unit and the exam date set to the start of the next testing window. Readiness is weighted the way the exam is, so a weak unit that carries 18% of the score pulls harder than one that carries 6%. Pre-written units come with worked explanations and an independently checked answer key; the rest are written by the agent when you open them.