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Complex Eigenvalues

Differential Equations · Section 7.6 · generated practice set

Complex eigenvalues, real solutions from Euler's formula, and the spiral sink / source / centre split.

Practice this set → Fresh numbers on every attempt. No account needed.

Method

When $det(A - lambda I) = 0$ has complex roots $lambda = alpha pm ieta$, the algebra is the same but the picture rotates.

Building real solutions

Take the eigenvector $mathbf{v} = mathbf{a} + imathbf{b}$ for $lambda = alpha + ieta$ (the conjugate pair gives nothing new). Then $$mathbf{x} = e^{alpha t}Big[c_1left(mathbf{a}coseta t - mathbf{b}sineta t ight) + c_2left(mathbf{a}sineta t + mathbf{b}coseta t ight)Big].$$ In practice: compute $mathbf{v}e^{lambda t}$, expand with Euler's formula, and take the real and imaginary parts as your two real solutions.

The phase portrait

  • $alpha < 0$ → spiral sink, asymptotically stable — inward spiral.
  • $alpha > 0$ → spiral source, unstable — outward spiral.
  • $alpha = 0$ → center — closed orbits. Stable, but not asymptotically stable: trajectories stay near the origin without approaching it.

$eta$ sets how fast the trajectory winds around and never affects stability. The direction of rotation comes from the sign of the off-diagonal entries, most easily found by evaluating $Amathbf{x}$ at a convenient point such as $egin{pmatrix} 1 \ 0end{pmatrix}$ and seeing which way the arrow points.

Definitions and theorems

Real solutions from a complex pair
If $lambda = alpha + ieta$ has eigenvector $mathbf{a} + imathbf{b}$, then $e^{alpha t}left(mathbf{a}coseta t - mathbf{b}sineta t ight)$ and $e^{alpha t}left(mathbf{a}sineta t + mathbf{b}coseta t ight)$ are real linearly independent solutions.
Classification
Complex eigenvalues $alpha pm ieta$ with $eta eq 0$: spiral sink if $alpha < 0$, spiral source if $alpha > 0$, center if $alpha = 0$.

Worked example

Classify the origin for $mathbf{x}' = egin{pmatrix} -1 & -4 \ 1 & -1end{pmatrix}mathbf{x}$.

  1. $ ext{tr}A = -2$, $det A = 1 + 4 = 5$, so $lambda^2 + 2lambda + 5 = 0$.
  2. Discriminant $4 - 20 = -16 < 0$, so $lambda = dfrac{-2 pm 4i}{2} = -1 pm 2i$.
  3. $alpha = -1 < 0$ and $eta = 2$.
  4. The origin is a spiral sink: trajectories wind around it while decaying like $e^{-t}$.
  5. They complete one full turn every $2pi/eta = pi$ units of time, shrinking by a factor $e^{-pi} approx 0.043$ each turn.

Common mistakes

  1. Using both conjugate eigenvalues. One of the pair gives both real solutions; the other repeats them.
  2. Letting $eta$ decide stability. Only the sign of $alpha$ matters.
  3. Calling a center asymptotically stable. Orbits are closed — they stay nearby but never approach.
  4. Leaving $i$ in the final answer. The general solution of a real system is real; the complex arithmetic is scaffolding.
  5. Guessing the spiral direction from the eigenvalues. They do not encode it — test the vector field at a point.

Practice it

Reading the method is not the same as being able to run it under time pressure. This set generates a new problem with new coefficients every attempt, marks each part separately, and shows the full worked solution.

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